4b+13=2(b+1)-1

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Solution for 4b+13=2(b+1)-1 equation: 



4b+13=2(b+1)-1

We move all terms to the left:

4b+13-(2(b+1)-1)=0



We calculate terms in parentheses: -(2(b+1)-1), so:

2(b+1)-1

We multiply parentheses

2b+2-1

We add all the numbers together, and all the variables

2b+1

Back to the equation:

-(2b+1)



We get rid of parentheses

4b-2b-1+13=0

We add all the numbers together, and all the variables

2b+12=0

We move all terms containing b to the left, all other terms to the right

2b=-12

b=-12/2

b=-6

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