4b+2(b-3)=18

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Solution for 4b+2(b-3)=18 equation: 



4b+2(b-3)=18

We move all terms to the left:

4b+2(b-3)-(18)=0

We multiply parentheses

4b+2b-6-18=0

We add all the numbers together, and all the variables

6b-24=0

We move all terms containing b to the left, all other terms to the right

6b=24

b=24/6

b=4

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