4b+20=b+5(b+4)-2b

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Solution for 4b+20=b+5(b+4)-2b equation:



4b+20=b+5(b+4)-2b
We move all terms to the left:
4b+20-(b+5(b+4)-2b)=0
We calculate terms in parentheses: -(b+5(b+4)-2b), so:
b+5(b+4)-2b
We add all the numbers together, and all the variables
-1b+5(b+4)
We multiply parentheses
-1b+5b+20
We add all the numbers together, and all the variables
4b+20
Back to the equation:
-(4b+20)
We get rid of parentheses
4b-4b-20+20=0
We add all the numbers together, and all the variables
=0
b=0/1
b=0

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