4b+20=b+5(b+4)-2b

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Solution for 4b+20=b+5(b+4)-2b equation: 



4b+20=b+5(b+4)-2b

We move all terms to the left:

4b+20-(b+5(b+4)-2b)=0



We calculate terms in parentheses: -(b+5(b+4)-2b), so:

b+5(b+4)-2b

We add all the numbers together, and all the variables

-1b+5(b+4)

We multiply parentheses

-1b+5b+20

We add all the numbers together, and all the variables

4b+20

Back to the equation:

-(4b+20)



We get rid of parentheses

4b-4b-20+20=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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