4b+290-40=b-50

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Solution for 4b+290-40=b-50 equation: 



4b+290-40=b-50

We move all terms to the left:

4b+290-40-(b-50)=0

We add all the numbers together, and all the variables

4b-(b-50)+250=0

We get rid of parentheses

4b-b+50+250=0

We add all the numbers together, and all the variables

3b+300=0

We move all terms containing b to the left, all other terms to the right

3b=-300

b=-300/3

b=-100

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