4b+3(-b-1)=2b-(3b-1)

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Solution for 4b+3(-b-1)=2b-(3b-1) equation: 



4b+3(-b-1)=2b-(3b-1)

We move all terms to the left:

4b+3(-b-1)-(2b-(3b-1))=0

We add all the numbers together, and all the variables

4b+3(-1b-1)-(2b-(3b-1))=0

We multiply parentheses

4b-3b-(2b-(3b-1))-3=0



We calculate terms in parentheses: -(2b-(3b-1)), so:

2b-(3b-1)

We get rid of parentheses

2b-3b+1

We add all the numbers together, and all the variables

-1b+1

Back to the equation:

-(-1b+1)



We add all the numbers together, and all the variables

b-(-1b+1)-3=0

We get rid of parentheses

b+1b-1-3=0

We add all the numbers together, and all the variables

2b-4=0

We move all terms containing b to the left, all other terms to the right

2b=4

b=4/2

b=2

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