4b+3(7+b)=56

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Solution for 4b+3(7+b)=56 equation: 



4b+3(7+b)=56

We move all terms to the left:

4b+3(7+b)-(56)=0

We add all the numbers together, and all the variables

4b+3(b+7)-56=0

We multiply parentheses

4b+3b+21-56=0

We add all the numbers together, and all the variables

7b-35=0

We move all terms containing b to the left, all other terms to the right

7b=35

b=35/7

b=5

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