4b+3(b+1)=7b+3

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Solution for 4b+3(b+1)=7b+3 equation: 



4b+3(b+1)=7b+3

We move all terms to the left:

4b+3(b+1)-(7b+3)=0

We multiply parentheses

4b+3b-(7b+3)+3=0

We get rid of parentheses

4b+3b-7b-3+3=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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