4b+6(b+2)=-6(1-b)

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Solution for 4b+6(b+2)=-6(1-b) equation: 



4b+6(b+2)=-6(1-b)

We move all terms to the left:

4b+6(b+2)-(-6(1-b))=0

We add all the numbers together, and all the variables

4b+6(b+2)-(-6(-1b+1))=0

We multiply parentheses

4b+6b-(-6(-1b+1))+12=0



We calculate terms in parentheses: -(-6(-1b+1)), so:

-6(-1b+1)

We multiply parentheses

6b-6

Back to the equation:

-(6b-6)



We add all the numbers together, and all the variables

10b-(6b-6)+12=0

We get rid of parentheses

10b-6b+6+12=0

We add all the numbers together, and all the variables

4b+18=0

We move all terms containing b to the left, all other terms to the right

4b=-18

b=-18/4

b=-4+1/2

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