4b-(-4)=(20b+20)/4

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Solution for 4b-(-4)=(20b+20)/4 equation:



4b-(-4)=(20b+20)/4
We move all terms to the left:
4b-(-4)-((20b+20)/4)=0
We add all the numbers together, and all the variables
4b-((20b+20)/4)+4=0
We multiply all the terms by the denominator
4b*4)-((20b+20)+4*4)=0
We add all the numbers together, and all the variables
4b*4)-((20b+20)=0
Wy multiply elements
16b^2=0
a = 16; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·16·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$b=\frac{-b}{2a}=\frac{0}{32}=0$

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