4b-11+3b=8(b-19)

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Solution for 4b-11+3b=8(b-19) equation: 



4b-11+3b=8(b-19)

We move all terms to the left:

4b-11+3b-(8(b-19))=0

We add all the numbers together, and all the variables

7b-(8(b-19))-11=0



We calculate terms in parentheses: -(8(b-19)), so:

8(b-19)

We multiply parentheses

8b-152

Back to the equation:

-(8b-152)



We get rid of parentheses

7b-8b+152-11=0

We add all the numbers together, and all the variables

-1b+141=0

We move all terms containing b to the left, all other terms to the right

-b=-141

b=-141/-1

b=+141

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