4b-18=3(1-6b)+b

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Solution for 4b-18=3(1-6b)+b equation: 



4b-18=3(1-6b)+b

We move all terms to the left:

4b-18-(3(1-6b)+b)=0

We add all the numbers together, and all the variables

4b-(3(-6b+1)+b)-18=0



We calculate terms in parentheses: -(3(-6b+1)+b), so:

3(-6b+1)+b

We add all the numbers together, and all the variables

b+3(-6b+1)

We multiply parentheses

b-18b+3

We add all the numbers together, and all the variables

-17b+3

Back to the equation:

-(-17b+3)



We get rid of parentheses

4b+17b-3-18=0

We add all the numbers together, and all the variables

21b-21=0

We move all terms containing b to the left, all other terms to the right

21b=21

b=21/21

b=1

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