4b-2(b-5)=-3+4b+9

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Solution for 4b-2(b-5)=-3+4b+9 equation: 



4b-2(b-5)=-3+4b+9

We move all terms to the left:

4b-2(b-5)-(-3+4b+9)=0

We add all the numbers together, and all the variables

4b-2(b-5)-(4b+6)=0

We multiply parentheses

4b-2b-(4b+6)+10=0

We get rid of parentheses

4b-2b-4b-6+10=0

We add all the numbers together, and all the variables

-2b+4=0

We move all terms containing b to the left, all other terms to the right

-2b=-4

b=-4/-2

b=+2

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