4b-3/b(b)+1=4/b

Solution for 4b-3/b(b)+1=4/b equation:

4b-3/b(b)+1=4/b

We move all terms to the left:

4b-3/b(b)+1-(4/b)=0


Domain of the equation: bb!=0

b!=0/1

b!=0

b∈R



Domain of the equation: b)!=0

b!=0/1

b!=0

b∈R


We add all the numbers together, and all the variables

4b-3/bb-(+4/b)+1=0

We get rid of parentheses

4b-3/bb-4/b+1=0

We calculate fractions


4b+(-3b)/b^2+(-4b)/b^2+1=0

We multiply all the terms by the denominator


4b*b^2+(-3b)+(-4b)+1*b^2=0

We add all the numbers together, and all the variables

b^2+4b*b^2+(-3b)+(-4b)=0

Wy multiply elements

b^2+4b^3+(-3b)+(-4b)=0

We get rid of parentheses

b^2+4b^3-3b-4b=0

We do not support ebpression: b^3