4b-32+(3b-68)=180

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Solution for 4b-32+(3b-68)=180 equation: 



4b-32+(3b-68)=180

We move all terms to the left:

4b-32+(3b-68)-(180)=0

We add all the numbers together, and all the variables

4b+(3b-68)-212=0

We get rid of parentheses

4b+3b-68-212=0

We add all the numbers together, and all the variables

7b-280=0

We move all terms containing b to the left, all other terms to the right

7b=280

b=280/7

b=40

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