4b-5(3b+10)=126

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Solution for 4b-5(3b+10)=126 equation: 



4b-5(3b+10)=126

We move all terms to the left:

4b-5(3b+10)-(126)=0

We multiply parentheses

4b-15b-50-126=0

We add all the numbers together, and all the variables

-11b-176=0

We move all terms containing b to the left, all other terms to the right

-11b=176

b=176/-11

b=-16

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