4b-68=b+12

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Solution for 4b-68=b+12 equation: 



4b-68=b+12

We move all terms to the left:

4b-68-(b+12)=0

We get rid of parentheses

4b-b-12-68=0

We add all the numbers together, and all the variables

3b-80=0

We move all terms containing b to the left, all other terms to the right

3b=80

b=80/3

b=26+2/3

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