4b-8(2-4b)=56

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Solution for 4b-8(2-4b)=56 equation: 



4b-8(2-4b)=56

We move all terms to the left:

4b-8(2-4b)-(56)=0

We add all the numbers together, and all the variables

4b-8(-4b+2)-56=0

We multiply parentheses

4b+32b-16-56=0

We add all the numbers together, and all the variables

36b-72=0

We move all terms containing b to the left, all other terms to the right

36b=72

b=72/36

b=2

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