4b-8)/3)=2b

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Solution for 4b-8)/3)=2b equation: 



4b-8)/3)=2b

We move all terms to the left:

4b-8)/3)-(2b)=0



Domain of the equation: 3)-2b!=0

b!=0/1

b!=0

b∈R



We multiply all the terms by the denominator


4b*3)-2b-8)=0

Wy multiply elements

12b^2=0

a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$b=\frac{-b}{2a}=\frac{0}{24}=0$

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