4b-8)/3)=2b

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Solution for 4b-8)/3)=2b equation:



4b-8)/3)=2b
We move all terms to the left:
4b-8)/3)-(2b)=0
Domain of the equation: 3)-2b!=0
b!=0/1
b!=0
b∈R
We multiply all the terms by the denominator
4b*3)-2b-8)=0
Wy multiply elements
12b^2=0
a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$b=\frac{-b}{2a}=\frac{0}{24}=0$

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