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4b^2+5b-75=0
a = 4; b = 5; c = -75;
Δ = b2-4ac
Δ = 52-4·4·(-75)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-35}{2*4}=\frac{-40}{8} =-5 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+35}{2*4}=\frac{30}{8} =3+3/4 $
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