4b2-10b=-b2-5

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Solution for 4b2-10b=-b2-5 equation: 



4b^2-10b=-b2-5

We move all terms to the left:

4b^2-10b-(-b2-5)=0

We add all the numbers together, and all the variables

4b^2-(-1b^2-5)-10b=0

We get rid of parentheses

4b^2+1b^2-10b+5=0

We add all the numbers together, and all the variables

5b^2-10b+5=0

a = 5; b = -10; c = +5;
Δ = b2-4ac
Δ = -102-4·5·5
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$b=\frac{-b}{2a}=\frac{10}{10}=1$

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