4b=2(b+1)+3(b-1)

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Solution for 4b=2(b+1)+3(b-1) equation:


Simplifying
4b = 2(b + 1) + 3(b + -1)

Reorder the terms:
4b = 2(1 + b) + 3(b + -1)
4b = (1 * 2 + b * 2) + 3(b + -1)
4b = (2 + 2b) + 3(b + -1)

Reorder the terms:
4b = 2 + 2b + 3(-1 + b)
4b = 2 + 2b + (-1 * 3 + b * 3)
4b = 2 + 2b + (-3 + 3b)

Reorder the terms:
4b = 2 + -3 + 2b + 3b

Combine like terms: 2 + -3 = -1
4b = -1 + 2b + 3b

Combine like terms: 2b + 3b = 5b
4b = -1 + 5b

Solving
4b = -1 + 5b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-5b' to each side of the equation.
4b + -5b = -1 + 5b + -5b

Combine like terms: 4b + -5b = -1b
-1b = -1 + 5b + -5b

Combine like terms: 5b + -5b = 0
-1b = -1 + 0
-1b = -1

Divide each side by '-1'.
b = 1

Simplifying
b = 1

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