4b=3(-3b+5)-2b

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Solution for 4b=3(-3b+5)-2b equation: 



4b=3(-3b+5)-2b

We move all terms to the left:

4b-(3(-3b+5)-2b)=0



We calculate terms in parentheses: -(3(-3b+5)-2b), so:

3(-3b+5)-2b

We add all the numbers together, and all the variables

-2b+3(-3b+5)

We multiply parentheses

-2b-9b+15

We add all the numbers together, and all the variables

-11b+15

Back to the equation:

-(-11b+15)



We get rid of parentheses

4b+11b-15=0

We add all the numbers together, and all the variables

15b-15=0

We move all terms containing b to the left, all other terms to the right

15b=15

b=15/15

b=1

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