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4b=38-2(b+4
We move all terms to the left:
4b-(38-2(b+4)=0
We calculate terms in parentheses: -(38-2(b+4), so:We add all the numbers together, and all the variables
38-2(b+4
determiningTheFunctionDomain -2(b+4+38
Back to the equation:
-(-2(b+4+38)
4b-(-2(b+42)=0
We calculate terms in parentheses: -(-2(b+42), so:
-2(b+42
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| 2x/3+x=90 | | 4/5b=32 | | 11=-k-5 | | 4(x+7)=2x+28+2x | | 13v+9+7+7=32 | | 3-2x5=1 | | -3+-3v=-12 | | 5x-15-7x=2x+34 | | 4x-4=52-3x | | 2y+8-5y=-28= | | 0.10m+3.95=23.75 | | -1=5x-8+3x | | 5+x3=2x8 | | 2(x-3)=16-3x | | 4(x-3)=49 | | 15x+3=x-6 | | 12+x=195 | | 4x+54=110 | | 20=k+1 | | r-4/8=r/6 | | 0.75(t-1)+4.25=5.75 | | n/8+7=-9 | | 5x+34=-2(-1-7x) | | 2x2x=1 | | 11=(3x-6) | | 5-2(x-1)=x | | 3g-14=1 | | 5x-2x=15-20 | | -2(-x-5)+5x+2=27 | | x=1+17/27 | | 4=f•4 | | –3=c/3− 5 |