4b=9-2(b+3)

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Solution for 4b=9-2(b+3) equation:



4b=9-2(b+3)
We move all terms to the left:
4b-(9-2(b+3))=0
We calculate terms in parentheses: -(9-2(b+3)), so:
9-2(b+3)
determiningTheFunctionDomain -2(b+3)+9
We multiply parentheses
-2b-6+9
We add all the numbers together, and all the variables
-2b+3
Back to the equation:
-(-2b+3)
We get rid of parentheses
4b+2b-3=0
We add all the numbers together, and all the variables
6b-3=0
We move all terms containing b to the left, all other terms to the right
6b=3
b=3/6
b=1/2

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