4c(1-c)=8

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Solution for 4c(1-c)=8 equation: 



4c(1-c)=8

We move all terms to the left:

4c(1-c)-(8)=0

We add all the numbers together, and all the variables

4c(-1c+1)-8=0

We multiply parentheses

-4c^2+4c-8=0

a = -4; b = 4; c = -8;
Δ = b2-4ac
Δ = 42-4·(-4)·(-8)
Δ = -112
Delta is less than zero, so there is no solution for the equation

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