4c+10c+15-2c=3(4c+5)

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Solution for 4c+10c+15-2c=3(4c+5) equation: 



4c+10c+15-2c=3(4c+5)

We move all terms to the left:

4c+10c+15-2c-(3(4c+5))=0

We add all the numbers together, and all the variables

12c-(3(4c+5))+15=0



We calculate terms in parentheses: -(3(4c+5)), so:

3(4c+5)

We multiply parentheses

12c+15

Back to the equation:

-(12c+15)



We get rid of parentheses

12c-12c-15+15=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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