4c+1=3+6c

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Solution for 4c+1=3+6c equation: 



4c+1=3+6c

We move all terms to the left:

4c+1-(3+6c)=0

We add all the numbers together, and all the variables

4c-(6c+3)+1=0

We get rid of parentheses

4c-6c-3+1=0

We add all the numbers together, and all the variables

-2c-2=0

We move all terms containing c to the left, all other terms to the right

-2c=2

c=2/-2

c=-1

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