4c+2(100-c)=268

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Solution for 4c+2(100-c)=268 equation: 



4c+2(100-c)=268

We move all terms to the left:

4c+2(100-c)-(268)=0

We add all the numbers together, and all the variables

4c+2(-1c+100)-268=0

We multiply parentheses

4c-2c+200-268=0

We add all the numbers together, and all the variables

2c-68=0

We move all terms containing c to the left, all other terms to the right

2c=68

c=68/2

c=34

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