4c+27=3c-3(6-2c)

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Solution for 4c+27=3c-3(6-2c) equation: 



4c+27=3c-3(6-2c)

We move all terms to the left:

4c+27-(3c-3(6-2c))=0

We add all the numbers together, and all the variables

4c-(3c-3(-2c+6))+27=0



We calculate terms in parentheses: -(3c-3(-2c+6)), so:

3c-3(-2c+6)

We multiply parentheses

3c+6c-18

We add all the numbers together, and all the variables

9c-18

Back to the equation:

-(9c-18)



We get rid of parentheses

4c-9c+18+27=0

We add all the numbers together, and all the variables

-5c+45=0

We move all terms containing c to the left, all other terms to the right

-5c=-45

c=-45/-5

c=+9

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