4c+28=21+3c

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Solution for 4c+28=21+3c equation: 



4c+28=21+3c

We move all terms to the left:

4c+28-(21+3c)=0

We add all the numbers together, and all the variables

4c-(3c+21)+28=0

We get rid of parentheses

4c-3c-21+28=0

We add all the numbers together, and all the variables

c+7=0

We move all terms containing c to the left, all other terms to the right

c=-7

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