4c+2=6(c-3)

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Solution for 4c+2=6(c-3) equation: 



4c+2=6(c-3)

We move all terms to the left:

4c+2-(6(c-3))=0



We calculate terms in parentheses: -(6(c-3)), so:

6(c-3)

We multiply parentheses

6c-18

Back to the equation:

-(6c-18)



We get rid of parentheses

4c-6c+18+2=0

We add all the numbers together, and all the variables

-2c+20=0

We move all terms containing c to the left, all other terms to the right

-2c=-20

c=-20/-2

c=+10

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