4c+3(2+c)=4c

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Solution for 4c+3(2+c)=4c equation: 



4c+3(2+c)=4c

We move all terms to the left:

4c+3(2+c)-(4c)=0

We add all the numbers together, and all the variables

4c+3(c+2)-4c=0

We add all the numbers together, and all the variables

3(c+2)=0

We multiply parentheses

3c+6=0

We move all terms containing c to the left, all other terms to the right

3c=-6

c=-6/3

c=-2

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