4c+3(c+2)=14

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Solution for 4c+3(c+2)=14 equation: 



4c+3(c+2)=14

We move all terms to the left:

4c+3(c+2)-(14)=0

We multiply parentheses

4c+3c+6-14=0

We add all the numbers together, and all the variables

7c-8=0

We move all terms containing c to the left, all other terms to the right

7c=8

c=8/7

c=1+1/7

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