4c+3(c+4)=2+7c+10

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Solution for 4c+3(c+4)=2+7c+10 equation: 



4c+3(c+4)=2+7c+10

We move all terms to the left:

4c+3(c+4)-(2+7c+10)=0

We add all the numbers together, and all the variables

4c+3(c+4)-(7c+12)=0

We multiply parentheses

4c+3c-(7c+12)+12=0

We get rid of parentheses

4c+3c-7c-12+12=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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