4c+3(c-2)=24

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Solution for 4c+3(c-2)=24 equation: 



4c+3(c-2)=24

We move all terms to the left:

4c+3(c-2)-(24)=0

We multiply parentheses

4c+3c-6-24=0

We add all the numbers together, and all the variables

7c-30=0

We move all terms containing c to the left, all other terms to the right

7c=30

c=30/7

c=4+2/7

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