4c+35=2c+28

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Solution for 4c+35=2c+28 equation: 



4c+35=2c+28

We move all terms to the left:

4c+35-(2c+28)=0

We get rid of parentheses

4c-2c-28+35=0

We add all the numbers together, and all the variables

2c+7=0

We move all terms containing c to the left, all other terms to the right

2c=-7

c=-7/2

c=-3+1/2

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