4c+35=2c+63

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Solution for 4c+35=2c+63 equation:



4c+35=2c+63
We move all terms to the left:
4c+35-(2c+63)=0
We get rid of parentheses
4c-2c-63+35=0
We add all the numbers together, and all the variables
2c-28=0
We move all terms containing c to the left, all other terms to the right
2c=28
c=28/2
c=14

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