4c+35=2c+63

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Solution for 4c+35=2c+63 equation: 



4c+35=2c+63

We move all terms to the left:

4c+35-(2c+63)=0

We get rid of parentheses

4c-2c-63+35=0

We add all the numbers together, and all the variables

2c-28=0

We move all terms containing c to the left, all other terms to the right

2c=28

c=28/2

c=14

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