4c+5(3-2c)=8c-3(c+8)

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Solution for 4c+5(3-2c)=8c-3(c+8) equation: 



4c+5(3-2c)=8c-3(c+8)

We move all terms to the left:

4c+5(3-2c)-(8c-3(c+8))=0

We add all the numbers together, and all the variables

4c+5(-2c+3)-(8c-3(c+8))=0

We multiply parentheses

4c-10c-(8c-3(c+8))+15=0



We calculate terms in parentheses: -(8c-3(c+8)), so:

8c-3(c+8)

We multiply parentheses

8c-3c-24

We add all the numbers together, and all the variables

5c-24

Back to the equation:

-(5c-24)



We add all the numbers together, and all the variables

-6c-(5c-24)+15=0

We get rid of parentheses

-6c-5c+24+15=0

We add all the numbers together, and all the variables

-11c+39=0

We move all terms containing c to the left, all other terms to the right

-11c=-39

c=-39/-11

c=3+6/11

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