4c+9=(8c+1(2c-11))/3

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Solution for 4c+9=(8c+1(2c-11))/3 equation: 



4c+9=(8c+1(2c-11))/3

We move all terms to the left:

4c+9-((8c+1(2c-11))/3)=0

We multiply all the terms by the denominator


4c*3)-((8c+1(2c-11))+9*3)=0

We add all the numbers together, and all the variables

4c*3)-((8c+1(2c-11))=0

Wy multiply elements

12c^2=0

a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$c=\frac{-b}{2a}=\frac{0}{24}=0$

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