4c-12=5(6-2c)

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Solution for 4c-12=5(6-2c) equation: 



4c-12=5(6-2c)

We move all terms to the left:

4c-12-(5(6-2c))=0

We add all the numbers together, and all the variables

4c-(5(-2c+6))-12=0



We calculate terms in parentheses: -(5(-2c+6)), so:

5(-2c+6)

We multiply parentheses

-10c+30

Back to the equation:

-(-10c+30)



We get rid of parentheses

4c+10c-30-12=0

We add all the numbers together, and all the variables

14c-42=0

We move all terms containing c to the left, all other terms to the right

14c=42

c=42/14

c=3

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