4c-12=8c-80

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Solution for 4c-12=8c-80 equation: 



4c-12=8c-80

We move all terms to the left:

4c-12-(8c-80)=0

We get rid of parentheses

4c-8c+80-12=0

We add all the numbers together, and all the variables

-4c+68=0

We move all terms containing c to the left, all other terms to the right

-4c=-68

c=-68/-4

c=+17

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