4c-2(c-8)=3+3c

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Solution for 4c-2(c-8)=3+3c equation: 



4c-2(c-8)=3+3c

We move all terms to the left:

4c-2(c-8)-(3+3c)=0

We add all the numbers together, and all the variables

4c-2(c-8)-(3c+3)=0

We multiply parentheses

4c-2c-(3c+3)+16=0

We get rid of parentheses

4c-2c-3c-3+16=0

We add all the numbers together, and all the variables

-1c+13=0

We move all terms containing c to the left, all other terms to the right

-c=-13

c=-13/-1

c=+13

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