4c-2=5(c+3)

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Solution for 4c-2=5(c+3) equation: 



4c-2=5(c+3)

We move all terms to the left:

4c-2-(5(c+3))=0



We calculate terms in parentheses: -(5(c+3)), so:

5(c+3)

We multiply parentheses

5c+15

Back to the equation:

-(5c+15)



We get rid of parentheses

4c-5c-15-2=0

We add all the numbers together, and all the variables

-1c-17=0

We move all terms containing c to the left, all other terms to the right

-c=17

c=17/-1

c=-17

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