4c-2c-8+10=6c-10+11

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Solution for 4c-2c-8+10=6c-10+11 equation: 



4c-2c-8+10=6c-10+11

We move all terms to the left:

4c-2c-8+10-(6c-10+11)=0

We add all the numbers together, and all the variables

4c-2c-(6c+1)-8+10=0

We add all the numbers together, and all the variables

2c-(6c+1)+2=0

We get rid of parentheses

2c-6c-1+2=0

We add all the numbers together, and all the variables

-4c+1=0

We move all terms containing c to the left, all other terms to the right

-4c=-1

c=-1/-4

c=1/4

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