4c-4(c+7)=4(c-4)-24

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Solution for 4c-4(c+7)=4(c-4)-24 equation: 



4c-4(c+7)=4(c-4)-24

We move all terms to the left:

4c-4(c+7)-(4(c-4)-24)=0

We multiply parentheses

4c-4c-(4(c-4)-24)-28=0



We calculate terms in parentheses: -(4(c-4)-24), so:

4(c-4)-24

We multiply parentheses

4c-16-24

We add all the numbers together, and all the variables

4c-40

Back to the equation:

-(4c-40)



We add all the numbers together, and all the variables

-(4c-40)-28=0

We get rid of parentheses

-4c+40-28=0

We add all the numbers together, and all the variables

-4c+12=0

We move all terms containing c to the left, all other terms to the right

-4c=-12

c=-12/-4

c=+3

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