4c-46+3c-30=c+50

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Solution for 4c-46+3c-30=c+50 equation:



4c-46+3c-30=c+50
We move all terms to the left:
4c-46+3c-30-(c+50)=0
We add all the numbers together, and all the variables
7c-(c+50)-76=0
We get rid of parentheses
7c-c-50-76=0
We add all the numbers together, and all the variables
6c-126=0
We move all terms containing c to the left, all other terms to the right
6c=126
c=126/6
c=21

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