4c-6+2c=7(c-6)+20

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Solution for 4c-6+2c=7(c-6)+20 equation: 



4c-6+2c=7(c-6)+20

We move all terms to the left:

4c-6+2c-(7(c-6)+20)=0

We add all the numbers together, and all the variables

6c-(7(c-6)+20)-6=0



We calculate terms in parentheses: -(7(c-6)+20), so:

7(c-6)+20

We multiply parentheses

7c-42+20

We add all the numbers together, and all the variables

7c-22

Back to the equation:

-(7c-22)



We get rid of parentheses

6c-7c+22-6=0

We add all the numbers together, and all the variables

-1c+16=0

We move all terms containing c to the left, all other terms to the right

-c=-16

c=-16/-1

c=+16

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