4c=(2c-5)+7

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Solution for 4c=(2c-5)+7 equation: 



4c=(2c-5)+7

We move all terms to the left:

4c-((2c-5)+7)=0



We calculate terms in parentheses: -((2c-5)+7), so:

(2c-5)+7

We get rid of parentheses

2c-5+7

We add all the numbers together, and all the variables

2c+2

Back to the equation:

-(2c+2)



We get rid of parentheses

4c-2c-2=0

We add all the numbers together, and all the variables

2c-2=0

We move all terms containing c to the left, all other terms to the right

2c=2

c=2/2

c=1

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