4c=3(2c-5)+7

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Solution for 4c=3(2c-5)+7 equation: 



4c=3(2c-5)+7

We move all terms to the left:

4c-(3(2c-5)+7)=0



We calculate terms in parentheses: -(3(2c-5)+7), so:

3(2c-5)+7

We multiply parentheses

6c-15+7

We add all the numbers together, and all the variables

6c-8

Back to the equation:

-(6c-8)



We get rid of parentheses

4c-6c+8=0

We add all the numbers together, and all the variables

-2c+8=0

We move all terms containing c to the left, all other terms to the right

-2c=-8

c=-8/-2

c=+4

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