4cos(2x)+10sinx-7=0

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Solution for 4cos(2x)+10sinx-7=0 equation:


Simplifying
4cos(2x) + 10sinx + -7 = 0

Remove parenthesis around (2x)
4cos * 2x + 10sinx + -7 = 0

Reorder the terms for easier multiplication:
4 * 2cos * x + 10sinx + -7 = 0

Multiply 4 * 2
8cos * x + 10sinx + -7 = 0

Multiply cos * x
8cosx + 10sinx + -7 = 0

Reorder the terms:
-7 + 8cosx + 10insx = 0

Solving
-7 + 8cosx + 10insx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '7' to each side of the equation.
-7 + 8cosx + 7 + 10insx = 0 + 7

Reorder the terms:
-7 + 7 + 8cosx + 10insx = 0 + 7

Combine like terms: -7 + 7 = 0
0 + 8cosx + 10insx = 0 + 7
8cosx + 10insx = 0 + 7

Combine like terms: 0 + 7 = 7
8cosx + 10insx = 7

Add '-10insx' to each side of the equation.
8cosx + 10insx + -10insx = 7 + -10insx

Combine like terms: 10insx + -10insx = 0
8cosx + 0 = 7 + -10insx
8cosx = 7 + -10insx

Divide each side by '8osx'.
c = 0.875o-1s-1x-1 + -1.25ino-1

Simplifying
c = 0.875o-1s-1x-1 + -1.25ino-1

Reorder the terms:
c = -1.25ino-1 + 0.875o-1s-1x-1

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